2x^+14x^2=-20x

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Solution for 2x^+14x^2=-20x equation:



2x^+14x^2=-20x
We move all terms to the left:
2x^+14x^2-(-20x)=0
We add all the numbers together, and all the variables
14x^2+2x-(-20x)=0
We get rid of parentheses
14x^2+2x+20x=0
We add all the numbers together, and all the variables
14x^2+22x=0
a = 14; b = 22; c = 0;
Δ = b2-4ac
Δ = 222-4·14·0
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{484}=22$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(22)-22}{2*14}=\frac{-44}{28} =-1+4/7 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(22)+22}{2*14}=\frac{0}{28} =0 $

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